Find the zeros of the polynomialf(x)=x2+7x+12 and verify the relation between its zeros and coefficients
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Hi friend,
f(x)=x²+7x+12=0
x²+3x+4x+12=0
x(x+3)+4(x+3)=0
(x+3)(x+4)=0
x+3=0
x=-3
x+4=0
x= -4
The zeroes of the polynomial are -3 and -4.
a=1,b=7,c=12
Sum of zeroes =-3+(-4)= -3-4= -7=-b/a
Product of zeroes=(-3)(-4)=12=c/a
hope it helps you
f(x)=x²+7x+12=0
x²+3x+4x+12=0
x(x+3)+4(x+3)=0
(x+3)(x+4)=0
x+3=0
x=-3
x+4=0
x= -4
The zeroes of the polynomial are -3 and -4.
a=1,b=7,c=12
Sum of zeroes =-3+(-4)= -3-4= -7=-b/a
Product of zeroes=(-3)(-4)=12=c/a
hope it helps you
Sumitmaheshwari:
Its correct
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