Question

Find the zeros of the polynomialf(x)=x2+7x+12 and verify the relation between its zeros and coefficients

Answer 1

Hi friend,

f(x)=x²+7x+12=0
x²+3x+4x+12=0
x(x+3)+4(x+3)=0
(x+3)(x+4)=0
x+3=0
x=-3
x+4=0
x= -4

The zeroes of the polynomial are -3 and -4.
a=1,b=7,c=12
Sum of zeroes =-3+(-4)= -3-4= -7=-b/a
Product of zeroes=(-3)(-4)=12=c/a

hope it helps you