Question

find the zeros of the polynomials 2x^2+5x-12 verify the relationship between zeros and confitiont

Answer 1

Answer:

2x^2+5x-12=0

2x^2-8x+3x-12=0

2x(x-4)+3(x-4)=0

(x-4)(2x+3)=0

here,x-4=0

x=4

and,2x+3=0

x=-3/2

Answer 2

Answer:

Here is your solution

2x^2 + 5x - 12 = 0

2x^2 + 8x - 3x - 12 = 0

2x (X+4) -3 (X+4) = 0

(2x-3) (X+4) = 0

2x-3 = 0 and X+4 = 0

X = 3/2 X = -4

Let X = 3/2 and B = -4

Sum of zeros (X+B) = 3/2 - 4

= 3/2 - 8/2

= -5/2

= - (coefficient of X ) / (coefficient of x^2 )

Product of zeros (XB) = (3/2) (-4)

= -12/2

(Constant term) / (Coefficient of X^2)