Math, asked by SparshhM15, 10 months ago

Find the zeros of the polynomials f (u) = 4 u2 + 8 u
Fast....

Answers

Answered by venkatlokesh011

Answer:

Step-by-step explanation:

4 u² + 8 u + 0 = 0

4 u ( u + 2 ) = 0

u = -2 or 0

SparshhM15: no

SparshhM15: ur answer is wrong

venkatlokesh011: Hey its correct. Please check

SparshhM15: no

SparshhM15: if u take 4 as common you will not get 8.. you will get 2 as answer

venkatlokesh011: Its 2 in place of 8

venkatlokesh011: I am sorry

SparshhM15: its ok

venkatlokesh011: Silly mistakes are done by me always

Answered by Anonymous

HEY MATE HERE IS YOUR ANSWER--

${4u}^{2} + 8u = 0 \\ \\ 4u(u + 2) = 0 \\ \\ u(u + 2) = \frac{0}{4} \\ \\ u = - 2 \: and \: 0$

SparshhM15: correct

Anonymous: thanks for branliest

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