Question

Find the zeros of the polynomials given below:
(i) p(x) = x-5
(ii) q(x) = x + 4
(iv) p(x) = ax + b (v) r(x) = x2 + 3x
(iii) h(x) = 6x - 1
(vi) (x) = x2 + 2x +1​

Answer 1

Answer:

1) x-5=0

x=5

hence the zero is 5

2) x+4=0

x=-4

hence the zero is -4

3) ax+b=0

ax=-b

x=-b/a

hence the zero is -b/a

4) 6x-1=0

6x=1

x=1/6

hence the zero is 1/6

5) x^2+2x+1

= x^2+x+x+1

= (x^2+x) (x+1)

= x(x+1) +1(x+1)

= ( x+1 ) ( x+1 )

= x+1=0

= x=-1

hence the zero of the polynomial

are -1 and -1

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Answer 2

Answer:

the above written is correct

Step-by-step explanation:

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