Question

find the zeros of the polynomials p(x)=6x2-3​

Answer 1

Step-by-step explanation:

the answer is 12 -3 =9

this answer is right?

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• p(x) = 6x$^2$ - 3

To Find:

• Zeroes of p(x)

Solution:

To find the zeroes,

p(x) = 0

=> 6x$^2$ - 3 = 0

=> 3(2x$^2$ - 1) = 0

=> 2x$^2$ - 1 = 0

=> 2x$^2$ = 1

=> x$^2 = \dfrac{1}{2}$

=> x = $\bf{\pm\dfrac{1}{\sqrt{2}}}$

Hope it helps!