Question

Find the zeros of the polynomials p(x) =(x-2)power of 2 - (x+2)power of 2 ​

Answer 1

Answer:

P(x)=(x−2)

2

−(x−2)

2

This is in the form of a

2

−b

2

P(x)=(x−2+x+2)(x−2−(x+2))

P(x)=2x(x−2−x−2)

P(x)=2x(−4)

P(x)=0

−8x=0

x=0

Hence,

x=0 is the zero of the polynomial P(x)

Answer 2

Answer:

0,2

Step-by-step explanation:

given,

(x-2)²-(x+2)²

using the identity -: a²-b² = (a+b)(a-b)

(x-2+x+2)(x-2-x-2)=0

(2x) (2x-4)=0

now,

2x=0. 2x-4=0

x=0/2=0. x=4/2=2

therefore the zeros of the polynomial are 0,2