Find the zeros of the polynomials p(x)=x2-4x+3and verify the relationship between zeros and coefficients
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Step-by-step explanation:
p(x) = x^2-4x+3
x^2-4x+3 = x^2-x-3x+3 = x(x-1)-3(x-1) = (x-1)(x-3)=
(x-1)(x-3) = 0 ----- x=1,3
the zeros of polynomial are 1 and 3
verification:
sum of zeros = 1+3 = 4
sum of zeros = -(co-efficient of x)/co-efficient of x^2
= -(-4)/1 =4
product of zeros = 1×3 =3
product of zeros = constant term / co-efficient of x^2
= 3/1 =3
hence verified.
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