Question

find the zeros of the polynomiyal x2+4x-12

Answer 1

Answer:

if I am not wrong

X=2; X=-6

Answer 2

Answer:

$x^{2} +4x-12=0\\x^{2} +6x-2x-12=0\\x(x+6)-2(x+6)=0\\Hence \\x+6=0\ or\ x- 2=0\\Hence\ x=-6 \ or \ 2$

Mark brainliest