Find the zeros of the polynomql x²-x -6
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x² -3x +2x -6 = 0
=> x(x-3)+2(x-3) = 0
=> (x-3)(x+2) = 0
Either
x-3 =0
=> x = 3
Or
x+2 =0
=> x = -2
Therefore the zeroes of the polynomial x²-x-6 are 3 and -2.
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