Math, asked by jackie8125, 9 months ago

Find the zeros of the polyomal p(x)=x3+9x-27

Answers

Answered by KaushalKishorKumar21
1

Answer

p(x)=x^3+9x-27

p(0)=x(0)^3+9(0)-27

p(0)=0+0-27

p(0)=-27

Answer -27

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