find the zeros of the polyomial 3xsquare+x-2
Answers
Answered by
0
Answer:
(x + 1)(3x - 2)
Step-by-step explanation:
⇒ 3x^2 + x - 2
{split 1x in such a manner, so that 3*(-2) = product of those parts}
⇒ 3x^2 + (3 - 2)x - 2
⇒ 3x^2 + 3x - 2x - 2
⇒ 3x(x + 1) - 2(x + 1)
⇒ (x + 1)(3x - 2)
Similar questions