Math, asked by bhavinivaswani, 9 months ago

find the zeros of the polyomial 3xsquare+x-2​

Answers

Answered by abhi569
0

Answer:

(x + 1)(3x - 2)

Step-by-step explanation:

⇒ 3x^2 + x - 2

     {split 1x in such a manner, so that 3*(-2) = product of those parts}

⇒ 3x^2 + (3 - 2)x - 2

⇒ 3x^2 + 3x - 2x - 2

⇒ 3x(x + 1) - 2(x + 1)

⇒ (x + 1)(3x - 2)

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