find the zeros of the quadratic polynomial 10x^2 -14x -12
Answers
hope this helps u
10x²-14x-12
10x² - 20x + 6x -12
(10x²-20x) ( 6x-12)
10x( x-2) +6 (x-2)
(x-2), (10x+6)
(x-2)=0 (10x+6) =0
x = 2, 10x= -6
x= 2 , -6/10
x = 2 , -6/10 are zero of the polynomial 10x²-14x-12
Answer:
The roots are 2,-3/5
Step-by-step explanation:
10x^2-14x-12
=5x^2-7x-6. (a=5,b=-7,c=-6)
discriminant=b^2-4ac
=(-7)^2-4*5*-6
=49+120
=169
therefore discriminant is greater than 0
so the roots are real roots
formula for finding roots=(-b+/-√b^2-4ac)/2a
=(7+/-√169)/10
=(7+/-13)/10
=7+13/10 ; 7-13/10
=20/10 ; -6/10
=2 ; -3/5
therefore the roots of the equation are 2,-3/5
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