find the zeros of the quadratic polynomial 2x^2-5x and verify the relationship between the zeros and coeffcients
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Answered by
0
Answer:
Step-by-step explanation:
First find the factors of 1. They are 1 and -1.
Then apply each on the place of x.
Let x=1
p(1)=2*1^2-5*1+1
(apply like this)
There's no zero of the given polynomial.
Hope it helps...
Answered by
0
Step-by-step explanation:
find the zeros of polynomial
p(x)=2x
2
−5x−12 and verify
the relationship between its zeros and coefficients
We will use side charge method
2π
2
−5x−12=0
it is in form ax
2
+bx+c=0
a=2
b=−5
c=−12
To find zeroes we will are relation
of coefficients as a formula
x=
2a
−b±
6
2
−4ac
=
2×2
−(−5)±
25−4×2×(−12)
=
4
5±
25+96
=
4
5±11
zeros or x
4
16
=4 and
4
5−11
=
4
−6
=
2
−3
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