Find the zeros of the quadratic polynomial 2x^2+x-10.Also verify the relationship between zeros and coefficients
Answers
Step-by-step explanation:
2x^2 +X-10
2x^2-4x+5x-10
2x(x-2)+5(x-2)
(2x+5)(x-2)
zeroes are -5/2 and 2
Zeroes are 2 , - 5/2 for quadratic polynomial 2x²+x-10 and relationship between zeros and coefficients is verified
Given:
quadratic polynomial 2x²+x-10
To Find:
zeros of the quadratic polynomial 2x²+x-10
verify the relationship between zeros and coefficients
Solution:
Quadratic Polynomial is of form ax² + bx + c where a≠0
Relationship between zeros and coefficients
Sum of zeroes = - b/a
Product of zeroes = c/a
2x² + x - 10
a = 2 , b = 1 , c = - 10
Sum of zeroes = -1/2
Product of zeroes = =10/2 = -5
2x² + x - 10
Using Middle term split
2x² -4x + 5x - 10
Taking 2x common in first two and 5 in last two
= 2x(x - 2) + 5(x - 2)
= (x - 2)(2x + 5)
To find zero equate each factor with zero
x - 2 = 0 => x = 2
2x + 5 = 0 => x = -5/2
Zeroes are 2 , - 5/2
Sum of zeroes = 2 - 5/2 = -1/2
Product of zeroes = 2(-5/2) = -5
Relationship between zeros and coefficients is verified.