Question

find the zeros of the quadratic polynomial 2x square -9 - 3x and verify the relationship between the zeros and the coefficient​

Answer 1

Step-by-step explanation:

$2 {x}^{2} - 3x - 9 = 0 \\ 2 {x}^{2} -6x + 3x - 9 = 0 \\ 2x(x -3) + 3(x - 3)= 0 \\ (2x + 3)(x - 3) = 0 \\ x = \frac{ - 3}{2}\: ,\:3 \\ \: \: \: \: \: \: \: \: \: \: \: \alpha \: \: \: , \: \: \beta \\ sum \: of \: zeroes: \\ \alpha + \beta = \frac{-b}{a} \\ \frac{ -3 }{2} +3 = \frac{ - (-3)}{2} \\ \frac{3}{2} = \frac{3}{2}$

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BY αβ= c/a

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