Question

find the zeros of the quadratic polynomial 3 x square - 75 and verify the relationship between zeros and coefficients​

Answer 1

Answer:

Step-by-step explanation:

3x^2 - 75=0

3x^2=75

x^2=25

x = \sqrt{25}

x= +5 or - 5

(Because if you square +5 or - 5,the result would be 25)

Answer 2

${3x}^{2} - 75 = 0$

${3x}^{2} = 75$

${x}^{2} = \frac{75}{3}$

${x}^{2} = 25$

$x = \sqrt {25}$

$x = + 5 \: or \: x = - 5$

Hence ,

$\alpha = + 5 \: and \: \beta = - 5$

Verification

$\alpha + \beta = 5 + ( - 5) \: = 0$

$\alpha + \beta = \frac{ - b}{a} = 0$

$\alpha \times \beta = 5 \times - 5 \: = - 25$

$\alpha \times \beta = \frac{c}{a} = \frac{ - 75}{3} = - 25$

Thus verified

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