Question

find the zeros of the quadratic polynomial 3x^2-4x+7

Answer 1

Zeros =alpha and beta

Another zeros are 1/alpha and 1/beta

Now

Sum of zeros =-b/a=4/3

Product of zeros=-7/3

Now taking another zeros

X^2-(sum of zeros)x+(product of zeros)

X^2-(1/alpha+1/beta)x+(1/alpha×1/beta)

X^2-(beta+alpha/alphabeta)x+(1/alphabeta)

X^2-(4/3/-7/3)x+(1/-7/3)

X^2-4/7x-3/7 is the req. Equation

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