Question

find the zeros of the quadratic polynomial 3x square -2 and verify​

Answer 1

$to \: find \: zeroes \: \\ 3 {x}^{2} - 2 = 0 \\ = > 3 {x}^{2} = 2 \\ = > {x}^{2} = \frac{2}{3} \\ = > x = \sqrt{ \frac{2}{3} } \: and \: x = - \sqrt{ \frac{2}{3} }$

Therefore The above values of x are the roots of the equation.

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