Question

Find the zeros of the quadratic polynomial 3x2-2 and verify the relationship between zeroes and co efficients

Answer 1

Answer:

-√(2/3),√(2/3) are zeroes of the given polynomial

Explanation:

Given Quadratic polynomial p(x) = 3x²-2

i) To find the zeroes of p(x),

we must take p(x)=0

3x²-2 = 0

=> 3x² = 2

=> x² = 2/3

=> x = ±√(2/3)

Verification:

Let m,n are two zeroes of the polyomial,

m = -√(2/√3)and n = √(2/3)

Compare p(x) with ax²+bx+c , we get

a = 3 , b = 0 , c=-2

i) sum of the zeroes =

= -√(2/3)+√(2/3)

= 0

= $\frac{-x- coefficient}{x^{2} -coefficient }$

ii) Product of the zeros

= [-√(2/3)][√(2/3)]

= -2/3

=$\frac{constant}{x^{2} -coefficient }$

Answer 2

Answer:

the above is the answer