Question

find the zeros of the quadratic polynomial √3x²-8x+4√3.​

Answer 1

Answer:

2√3 ; 2/√3

Step-by-step explanation:

√3x² - 8x + 4√3 = 0

√3x² - 6x - 2x + 4√3 = 0

√3x ( x - 2√3) - 2 ( x - 2√3 ) = 0

( x - 2√3 ) ( √3x - 2 ) = 0

x = 2√3

x = 2/√3

Hope it Helps

Answer 2

Answer:

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