Question

find the zeros of the quadratic polynomial √3y^2+10y+7√3​

Answer 1

Step-by-step explanation:

10Y can be written as (7+3)Y

so by modifying the question

√3Y²+(7+3)Y+7√3

√3Y²+7Y+3Y+7√3

Y(√3Y+7)+√3(√3Y+7)

(Y+√3)(√3Y+7)

so for zeroes

Y=-√3 or -7/√3

the second one is not rationalised

so Y=-7×√3/√3×√3

$y = \frac{ - 7 \sqrt{3}}{3}$

hope it helps

Answer 2

Hope you will better understand