Question

find the zeros of the quadratic polynomial 4√3y^2+5y-√3​

Answer 1

Answer:

Hi friend ,

4√3 x^2 + 5x -2√3 (splitting the middle term)

=4√3 x^2 +(8-3)x -2√3

=4√3(√3x+2)-√3(√3x+2)

= (√3x+2) (4x-3)

x = -2/√3

x = √3/4

So, alpha + beta = -b/a

= -5/4√3

Sum of zeros = -2/√3 + √3/4

= -5/4√3

Alpha×beta = c/a

= -2√3/4√3

= -1/2

Product of zeros = -2/√3 × √3/4

= -2√3/4√3

= -1/2

Since the products and sum of zeros are same...Hence verified..

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Hope this helped u..

PLZ MARK AS BRAINLIEST..

Hope this helped u..

PLZ MARK AS BRAINLIEST...