find the zeros of the quadratic polynomial 4 root 3 X square + 5 x minus 2 root 3 and verify the relationship between the zeros and the coefficients.
Answers
Answered by
425
Heya !!!
P(X) => 4✓3X²+5X-2✓3
=> 4✓3X² + 8X -3X - 2✓3
=> 4X ( ✓3X + 2) - ✓3( ✓3X + 2)
=> (✓3X +2) ( 4X- ✓3) = 0
=> (✓3X+2) = 0 OR (4X-✓4) = 0
=> X = -2/✓3 OR X = ✓4/4
Let Alpha = -2/✓3 and Beta = ✓4/4
Relationship between zeroes and Coefficient
Sum of zeroes = Alpha + Beta = ( -2/✓3 + ✓4/4) = -8 + 4/4✓3 = -5/ 4✓3 = - (Coefficient of X/Coefficient of X²)
And,
Product of zeroes = Alpha × Beta = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU....... :-)
P(X) => 4✓3X²+5X-2✓3
=> 4✓3X² + 8X -3X - 2✓3
=> 4X ( ✓3X + 2) - ✓3( ✓3X + 2)
=> (✓3X +2) ( 4X- ✓3) = 0
=> (✓3X+2) = 0 OR (4X-✓4) = 0
=> X = -2/✓3 OR X = ✓4/4
Let Alpha = -2/✓3 and Beta = ✓4/4
Relationship between zeroes and Coefficient
Sum of zeroes = Alpha + Beta = ( -2/✓3 + ✓4/4) = -8 + 4/4✓3 = -5/ 4✓3 = - (Coefficient of X/Coefficient of X²)
And,
Product of zeroes = Alpha × Beta = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU....... :-)
Purvein:
thnx
Answered by
146
Answer:
Step-by-step explanation:
I hope it will help you
Attachments:
Similar questions