Find the zeros of the quadratic polynomial 4x^-4x-3 and verify the relation between its zeros and coefficient
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Hey
Here is ur answer
P(x) = 4x2- 4x-3
By using splitting middle term method we get
4x2-6x+2x-3
=2x(2x-3)+ 1(2x-3)
=(2x+1)(2x-3) =0
x= -1/2 and x = 3/2
let alpha = -1/2 and beta = 3/2
Alpha + beta = -1/2+3/2
Alpha + beta = 2/2= 1 ➖ (1)
Now
- coefficient of x/coefficient of x2= -(-4)/4 = 1 ➖ (2)
From equation 1 and. 2
We get
Alpha + beta =. - coefficient of x/coefficient of x2
Now
Alpha*beta = -1/2*3/2= -3/4➖ 3
Constant term/coefficient of x2= -3/4 ➖ 4
From equation 3 and 4 we get
Alpha * beta = constant term/coefficient of x2
Hope it helps you
Here is ur answer
P(x) = 4x2- 4x-3
By using splitting middle term method we get
4x2-6x+2x-3
=2x(2x-3)+ 1(2x-3)
=(2x+1)(2x-3) =0
x= -1/2 and x = 3/2
let alpha = -1/2 and beta = 3/2
Alpha + beta = -1/2+3/2
Alpha + beta = 2/2= 1 ➖ (1)
Now
- coefficient of x/coefficient of x2= -(-4)/4 = 1 ➖ (2)
From equation 1 and. 2
We get
Alpha + beta =. - coefficient of x/coefficient of x2
Now
Alpha*beta = -1/2*3/2= -3/4➖ 3
Constant term/coefficient of x2= -3/4 ➖ 4
From equation 3 and 4 we get
Alpha * beta = constant term/coefficient of x2
Hope it helps you
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