find the zeros of the quadratic polynomial 6 square + 7 x + 2 and verify the relationship between the zeros and coefficients
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Step-by-step explanation:
Equation is 6x^2+7x+2
we need to find the zeores so,
let us split middle term
then,
6x^2+4x+3x+2
2x(3x+2)+1(3x+2)
(2x+1)(3x+2)
so for,
2x+1 = 0
2x= -1
x= -1/2
and for,
3x+2= 0
3x= -2
x = -2/3
so zeroes are -1/2 and -2/3
then we need to verify the relationship between the zeroes and coefficient.
then,
let the zeroes m and n
then, (ax^2+bx+c)
m+n= -b/a
and,
mn=c/a
so, we know that m= -1/2 and n= -2/3
so, 1/2+(-2/3)= -7/6 [According to m+n= -b/a]
so,
-1/2-2/3= -7/6
-3-4/6= -7/6
-7/6 = -7/6
AND
-1/2×-2/3=2/6[According to mn=c/a]
1/3=1/3
VERIFIED
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