Question

Find the zeros of the quadratic polynomial 6x square - 3 and the relation between the zeros and its coefficient

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Answer 1

Answer:

let polynomial p(X)=6x^2-3. (a=6,b=0,c=-3)

for zeroes p(X)=0

6x^2-3=0

X=+1/√2,-1/√2

these are the roots of the given polynomial

alpha=+1/√2

beeta=-1/√2

sum of the roots (alpha+beeta) = -b/a

b is the coefficient of X term

a is the coefficient of x^2 term

+1/√2+(-1/√2)=0/2

0=0. (verified)

product of the roots (alpha×beeta)=c/a

c is the constant term

a is the coefficient of x^2 term

(1/√2)(-1/√2)=-3/6

-1/2=-1/2. ( verified)