Question

find the zeros of the quadratic polynomial 6x square - 7 x minus 3 and verify the relation between its zeros and coefficient​

Answer 1

$\huge{\underline{\sf{\red{Answer}}}}$

$\implies$ 6x² - 7x - 3

$\implies$ 6x² - 9x + 2x - 3

$\implies$ 3x(2x -3) + 1 (2x-3)

$\implies$ (3x+1) (2x-3)

➤zeros are

x = $\frac{ - 1}{3}$

and

x = $\frac{3}{2}$

$\large\underline\mathfrak{verifying\; the\: relationship}$

➤α + β = $\frac{ - b}{a}$

$\implies$ $\frac{3}{2}$ + $\frac{ - 1}{3}$ = $\frac{7}{6}$

➤α × β = $\frac{c}{a}$

$\implies$ $\frac{ - 1}{3}$ × $\frac{2}{3}$ = $\frac{ - 1}{2}$

hence verification proved