Question

find the zeros of the quadratic polynomial 6x² + 29 X + 35 and verify the relationship between the zeros and the coefficient of the polynomial.​

Answer 1

Step-by-step explanation:

let p(x) be 6x^2+29x+35

6x^2+29x+35 = 6x^2+15x+14x+35

= 3x(2x+5)+7(2x+5) =(3x+7)(2x+5)

(3x+7)(2x+5)=0

zeros of p(x) are -7/3 and -5/2

verification:

sum of zeros = -(7/3+5/2) = -(14+15)/6 = -29/6

sum of zeros = -(co-efficient of x)/(co-efficient of x^2)

= -29/6

product of zeros = (-7/3) (-5/2) = (7×5)/(3×2) = 35/6

product of zeros = constant term / co-efficient of x^2

=35/6

hence verified.

Answer 2

Step-by-step explanation:

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