Question

Find the zeros of the quadratic polynomial "6x²-3-7x"

Answer 1

6x^2-7x-3=0
6x^2+2x-9x-3=0
2x(3x+1)-3(3x+1)=0
(2x-3)(3x+1)=0
x=3/2 ,x=-1/3

Answer 2

6x2-7x-3=6x2-9x+2x - 3
=3x(2x-3)+1(2x - 3)
=(2x-3)(3x+1)
x=3/2,-1/3