Question

Find the zeros of the quadratic polynomial 6x2-3-7x and verify the relationship

Answer 1

Step-by-step explanation:

6x2-3-7x

6x2-7x-3

d=b2-4ac

d=-(7)²-4(6)(-3)

d=49+72

d=121

x=-b+-√d/2a

x=-(-7)+-√121/2(6)

x=7+-11/12

x=7+11/12

x=18/12

x=3/2

x=7-11/12

x=-4/12

x=-1/3

for relationships α+β=-b/a

=-(-7)/6=7/6

verified...

for relationships αβ=c/a=-3/6

verified...

hope its help