Question

find the zeros of the quadratic polynomial (8$8 x^{2} -4$ and verify the relation between the zeros and coefficients

Answer 1

Hi there !

8x² - 4 = 0
a = 8
b = 0
c = -4


x² = 4/8
x² = 1/2

x = -1/√2 , 1/√2




 Zeroes = -1/√2 , 1/√2

Let ,
α = -1/√2
β = 1/√2



Sum of zeroes = α + β
                       = -1/√2 + 1/√2
                       = 0  
                       = -b/a               [ -b/a = 0/8 = 0 ]


Product of zeroes =  αβ 
                             = -1/√2 × 1/√2
                             = -1/2
                             = c/a               [ c/a = - 4/8  = -1/2 ]


Hope this Helps You !!