Question

Find the zeros of the quadratic polynomial 8x^2-21-22x and verify the relationship between zeros

and coefficients of the polynomial.

Answer 1

We find the roots of 8x²-21-22x by equating it to zero, then solving for the values of x


8x²-21-22x = 0

8x² - 22x -21 = 0

8x² - 28x + 6x - 21 = 0

4x(2x - 7) + 3(2x - 7) = 0

(4x + 3)(2x - 7) = 0


Either:

4x + 3 = 0

x = -3/4

or 

2x - 7 = 0

x = 7/2


The coefficients help us in getting the roots. In factorization, we get two number whose sum is the coefficient of x and the product = the product of the coefficient of x² and the constant term.

Answer 2

Answer:

Step-by-step explanation:

We find the roots of 8x²-21-22x by equating it to zero, then solving for the values of x

8x²-21-22x = 0

8x² - 22x -21 = 0

8x² - 28x + 6x - 21 = 0

4x(2x - 7) + 3(2x - 7) = 0

(4x + 3)(2x - 7) = 0

Either:

4x + 3 = 0

x = -3/4

or

2x - 7 = 0

x = 7/2

The coefficients help us in getting the roots. In factorization, we get two number whose sum is the coefficient of x and the product = the product of the coefficient of x² and the constant term.