Question

find the zeros of the quadratic polynomial a(x)=6x2_3_7 x​

Answer 1

Answer:

$x = \frac{3}{2}$

$x = - \frac{1}{3}$

Step-by-step explanation:

$6 {x}^{2} - 7x - 3$

$6 {x}^{2} - 9x + 2x - 3$

$3x(2x - 3) + 1(2x - 3)$

$(3x + 1)(2x - 3)$

$x = - \frac{1}{3}$

$x = \frac{3}{2}$