Question

find the zeros of the quadratic polynomial and find the relationship 3y²-60-8y​

Answer 1

3y^2-8y-60

by splitting middle term method

3y^2 -18y +10y -60 =0

3y(y-6) +10(y-6) =0

(y-6)(3y+10) =0

y-6=0. ,. 3y+10=0

y=6. ,. y=-10/3

please follow me