Question

find the zeros of the quadratic polynomial and verify the relationship between the zeros and it's coefficients f(x)=s^2-(1+2✓2)s+✓28​

Answer 1

Step-by-step explanation:

zeros = -b+√b^2-4ac/2

and -b-√b^2-4ac/2

when we add these two -2b/2

=-b/1=-b/a

when we multiply it is c/a

so sum of roots =( 1+2√2)/1=-b/a

product of roots =2√7=√28=c/a