find the zeros of the quadratic polynomial and verify the relationship between zeros and their question first 6 x square - 3 - 7x
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Answer:
zeroes of the polynomial: -1/3 and 3/2
Step-by-step explanation:
6x²-7x-3 [A=6, B=-7, C=-3]
=6x²-9x+2x-3 (middle term splitting)
=(6x²-9x)+(2x-3)
=3x(2x-3)+1(2x-3)
=(3x+1)(2x-3)
a(x)=-1/3 b(x)=3/2
verification:-
a(x)+b(x)=-B/A
=-1/3+3/2=7/6
=7/6=7/6 (verified)
a(x)*b(x)=C/A
=-1/3*3/2=-3/6
=-3/6=-3/6 (verified)
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