Question

Find the zeros of the quadratic polynomial and Verify
the relationship between
the cofficients X²- 10X + 25 =0​

Answer 1

Answer:

first you have to split it

X2 -10x + 25 =0

x2 -(5x-5x) + 25 =0

x2-5x -5x + 25

x(x-5) -5 (x-5)

(x-5) (x-5)

let p(x) = x2-10x+25 the zeros is (x-5)(x-5)

when it happens x=5 , x=5

The relationship of polynomial is

sum of zero = -b/a

product of zero = c/a

Here a=1 , b=-10 ,c=25

sum of the zero =

5+5 = -(-10)/1

10 =10 (verify)

Now you have to find product of zero

5×5 =25/1

25 =25 (verify)

I hope you will understand. about it

Thank you

Answer 2

x² - 10x + 25 = 0

x² - 5x - 5x + 25 = 0

x (x - 5) -5 (x - 5) = 0

(x - 5) (x - 5) = 0

therefore, zeroes are

x - 5 = 0 and x - 5 = 0

x = 5 x = 5

sum of zeroes = - coefficient of x / coefficient of x²

5 + 5 = 10 = -(-10) / 1 = 10

product of zeroes = constant term / coefficient of x²

5*5 = 25 = 25 / 1 = 25

I hope it helps u buddy

I hope it helps u buddy plz mark it as brainliest