Question

Find the zeros of the quadratic polynomial and verify the relationship between the zeros and Coefficients. 4u² + 8u

Answer 1

Answer:

p(x) = 4u²+8u

4u ( u + 2 ) = 0

[4u + 0 ] [ u + 2 ] ------> factorized form

hence ,

u = 0

u = -2

Here ,

a = 4

b = 8

c = 0

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2

= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0

= c/a = 0/4 = 0

Answer 2

Answer:

4u^2+8u=0

4u(u+2)=0

u+2=0

hence ,

u = 0

u =-2

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2

= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0

= c/a = 0/4 = 0

Step-by-step explanation:

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