Find the zeros of the quadratic polynomial f(x)=3x^2-11x+10 and then verify the relationship between the zeros and its cofficient
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Step-by-step explanation:
3x^2-11x+10
d=b^2-4ac
=(-11)^2-4*3*10
=121-120
=1
x=-b+-√d/3a=-(-11)+-√1/2*3
=11+-1/6
=12/6 or 10/6
=2 or 5/3
coefficient=3
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