Question

Find the zeros of the quadratic polynomial f (x)=6x^2-3 and verify the relationship between the zeros and its coefficients

Answer 1

Thus so

THUS THE QUADRATIC EQUATION IS
➡ 6X² - 3
. 6X² + 0 X - 3
. 6X² + ROOT 18X - ROOT 18X - 3
. 3ROOT 2 X ( ROOT 2 X + 1 ) - 3 ( ROOT 2 X + 1 )
. X = 1 / ROOT 2
. X = -1 / ROOT 2

THUS AS 1 / ROOT 2 + ( - 1 / ROOT 2 ) = 0
➡ - B / A = 0

AS 1 / ROOT 2 ❌ - 1 / ROOT 2 = -1 / 2
➡ C / A = -3 / 6 = -1 / 2

THUS IT S IT

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Answer 2

Here is the answer and verification is
a+b=-b/a
1/2^1/2+(-1/2^1/2)=0
a*b=c/a
1/2^1/2*(-1/2^1/2)=-1/2=-3/6