Question

find the zeros of the quadratic polynomial f x is equal to 6 x square - 7 x + 3 and verify the relationship between zero and coefficient​

Answer 1

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Answer 2

f(x) = $6x^{2} - 7x + 3$

   0 = $6x^{2}$ - 9x + 2x + 3                    

   0 = 3x (2x - 3) -1 (2x -3)

   0 = (3x -1) (2x -3)

Therefore, (3x -1)=0  or   (2x -3)=0

x= 1/3 or x=3/2

Hence, the zeroes of f(x) are 1/3 and 3/2.