find the zeros of the quadratic polynomial p(x) = 6x²_3_7x.
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Let 6x2 - 7x-3 be p(x) =0
so,6x2 - 7x-3 =0
6x2 - (9-2) x -3
6x2 - 9x + 2x -3
(6x2 - 9x)(2x-3)
3x(2x-3) +1 (2x-3)
(3x +1) (2x -3) = 0
⇒ 3x +1 = 0
⇒ 2x -3 = 0
⇒ x =3/2
⇒ x = - 1/3
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