Question

find the zeros of the quadratic polynomial p(x)=6x²-3-7x
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Answer 1

Answer:

=6x²-7x-3 =6x²+2x-9x-3 =2x( 3x+1)-3(3x+1) =(2x-3)(3x+1) ⇒2x-3=0 or ⇒3x +1=0 ⇒x=3/2 or ⇒ x= - 1/3 α=3/2 ,β= - 1/3

Step-by-step explanation:

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