Question

find the zeros of the quadratic polynomial P(x)= x^2-11x+28

Answer 1

Heya !

$\alpha + \beta = - b \div a$
a=2 , b=(-11) , c=28

sum= -(-11)/2

=+11/2

$\alpha \times \beta = c \div a$
product = 28/2
= 14