Question

find the zeros of the quadratic polynomial under root 3x^2-8x+4root 3​

Answer 1

Answer:

3x² - 8x + 4root3 = 0

Using the Quadratic Formula

x =

$\frac{8 + - \sqrt{ {8}^{2} - 4 \times 3 \times 4 \sqrt{3} } }{2 \times 3}$

=> x = {8 +- root(64 - 48root3)}/6

=> x =

$\frac{4 + 2 \sqrt{4 - 3 \sqrt{3} } }{3} and \frac{4 - 2 \sqrt{4 - 3 \sqrt{3} } }{3}$

HOPE THIS HELPS...