Question

Find the zeros of the quadratic polynomial x^2+12x+32

Answer 1

Answer:

x^2+12x+32

x^2+(8+4)x+3

x^2+8x+4x+32

x(x+8)+5(x+8)

(x+5)(x+8)

Answer 2

X^2 + 12X + 32 = 0

X^2 + (8 + 4)X + 32 = 0

X^2 + 8X + 4X + 32 = 0

X(X + 8) + 4(X + 8) = 0

(X + 4) + (X + 8) = 0

X + 4 = 0 OR X + 8 = 0

THEREFORE, X = - 4 OR X = - 8