Question

Find the zeros of the quadratic polynomial X^2-3 plz solve step by step to be as brainlist

Answer 1

Taking x² - 3 = 0
⇒ (x + √3) (x - √3) = 0 

Since, (a+b)(a-b) = a² - b²

So, the zeroes are √3 and - √3 

Answer 2

Given Equation is x^2 - 3.

= > x^2 - 3 = 0

= > x^2 = 3

$= x = \sqrt{3} , - \sqrt{3}$


Therefore $\sqrt{3} , - \sqrt{3}$ are zeroes of the polynomial.


Hope this helps!