Question

Find the zeros of the quadratic polynomial x
2+3x-10 and
verify the relation between its zeros and coefficients

Answer 1

Hello friends!!

Here is your answer :

${x}^{2} + 3x - 10$

First we have to factorize it.


${x}^{2} + 5x - 2x - 10$


${x}(x + 5) - 2(x + 5)$



$(x + 5)(x - 2)$



x + 5 = 0

x = - 5


x - 2 = 0

x = 2


Zeroes are 2, - 5.


Verification :

(i) L. H. S.

$\alpha + \beta$

$= 2 + ( -5)$


$= 2 - 5$

$= - 3$



R. H. S

$= \frac{ - coefficient \: \: of \: \: x}{ \: coefficient \: \: of \: \: {x}^{2} }$


$\frac{ - 3}{1}$


$= - 3$


L. H. S = R. H. S


(ii) L. H. S.

$\alpha \beta$


$= 2 \times - 5$



$= 10$


R. H. S


$= \frac{constant \: \: term}{coefficient \: \: of \: \: {x}^{2} \: }$


$= \frac{10}{1}$


$= 10$



L. H. S = R. H. S.


Hence verified.

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Hope it helps you.. ☺️☺️

Answer 2

Here is your answer

HOPE THIS ANSWER HELP YOU!!!