Question

find the zeros of the quadratic polynomial x^2 - 4x - 32 and verify the relationship between the zeros and coefficient of the polynomial​

Answer 1

Step-by-step explanation:

Let f(x) = 4x2 ˗ 4x ˗ 3 = 4x2 ˗ (6x ˗ 2x) ˗ 3 = 4x^2 ˗ 6x + 2x ˗ 3 = 2x (2x ˗ 3) + 1(2x ˗ 3) = (2x + 1) (2x ˗ 3) To find the zeroes, set f(x) = 0 (2x + 1) (2x ˗ 3)= 0 2x + 1 = 0 or 2x ˗ 3 = 0 x = -1/2 or x = 3/2 Again, Sum of zeroes = (-1/2) + (3/2) = (-1+3)/2 = 2/2 = -b/a = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = (-1/2)(3/2) = (-3)/4 = c/a = Constant term / Coefficient of x2Read more on Sarthaks.com - https://www.sarthaks.com/694814/find-zeros-quadratic-polynomials-3and-verify-relationship-between-zeros-coefficients