Question

find the zeros of the quadratic polynomial x^2+9x+18 , and verify the relationship between the zeros and the coefficients​

Answer 1

Answer:

x^2+9x+18

By factorization

x^2+3x+6x+18

x(x+3)+6(x+3)

x+6=0. x+3=0

x=-6. x=-3

alpha= -6. Beta= -3

Relationship between zeroes and coefficients

Sum of zeroes(alpha+beta)=-6+(-3)=-6-3=-9

Product of zeroes(alpha×beta)=18×1=18

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x= -6

x= -3. ::;;;;;;;;;;;;

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